Walmart company estimates that the computer they plan to buy in 18 months will cost $4,200. How much money should be deposited now into an account paying 5.75 % interest, compounded monthly so there will be enough money to pay cash for the computer in 18 months?
Walmart company estimates that the computer they plan to buy in 18 months will cost $4,200.
2 Answers
Let's use the equation A = P(1+r/n)nt to solve this problem.
The target value they need to have at the end is A = $4200.
The interest rate of 5.75% means that r = 0.0575.
Monthly compounding means they will compound the interest 12 times per year so n = 12.
The 18 months needed is 1.5 years so t = 1.5.
We need to find P.
Solving the interest equation for P gives
P = A(1+r/n)-nt
Plugging in the values gives P = $4200(1+0.0575/12)-12*1.5 = $3853.73
Note, you must round up:
At P = $3853.72 (rounded down value) they will wind up with $4199.99 and will be a penny short.
At P = $3853.73 (rounded up value) they will wind up with $4200.00, just enough to buy the computer.
Walmart company estimates that the computer they plan to buy in 18 months will cost $4,200. How much money should be deposited now into an account paying 5.75 % interest, compounded monthly so there will be enough money to pay cash for the computer in 18 months?
Compound interest formula:
A = P(1+r/n)^(nt)
P = principal amount (what we're looking for)
r = annual rate of interest (.0575)
t = number of years the amount is deposited or borrowed for. (18months translate to 1.5 years)
A = amount of money accumulated after n years, including interest. (4200)
n = number of times the interest is compounded per year (12)
4200 = P(1+.0575/12)^(12*1.5)
4200 = P(1.00479167)^18
4200/(1.00479167)^18 = P
4200/1.089854 = P
$3853.73 = P






