algebra 1 & it's hard for me so I am seeking the answer. please help!
what is the answer for this 36y4-25y2 ?
You need to factor this. First factor out a y2.
25 = 52
The factorization of a2-b2 is always (a-b)(a+b). This is called the difference of two squares.
So by the difference of two squares the factorization is y2(6y-5)(6y+5).
If by chance this is 36y4-25y2=0, then we'd need to take it one step further. With our factorization we set y2=0 to get y=0, 6y-5 =0 gives y = 5/6, and 6y+5 =0 gives y = -5/6.
Hope this helps!