math question
the product of two consecutive integers is 89 more than their sum. find the integers
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3 Answers
interpetation is crucial:
x(x+1) = x + (x+1) + 89
x^2 + x = 2x + 90
x^2 - x - 90 = 0
(x-10)(x+9) = 0
x = -9 or 10
10 is the root to use => the two numbers are 10 and 11
Okay so lets call the product = x*(x + 1)
The sum would be = x + (x +1)
This is what they tell us: x*( x + 1 ) = 89 + x + (x + 1)
From there on, we have: x^2 + x = 89 + 2x + 1
Put everything on one side: x^2 - x - 90 = 0
Factoring, we have: (x - 10)*(x + 9) = 0
If we use x = 10, then numbers are 10 and 11
Or if we use x = -9, then numbers are -9 and -8.
11*10=110
11+10=21
110-21=89



Comments
-9 and -8 are also plausible solutions.
- Roberto C. 12/17/2012