(5x^4+2x^3-9x+12)÷(x^2-3x+4)
(5x^4+2x^3-9x+12)÷(x^2-3x+4)
5x2 + 17x +31
x2 -3x + 4 /----------------------------------------------------
5x4 +2x3 +0x2 -9x +12
5x4 -15x3 +20x2
17x3 -20x2
17x3 -51x2 +68x
31x2 -77x
31x2 -93x +124
16x - 112
So the polynomial and modulus:
5x2 +17x +31 + (16x - 112)/(x2 -3x +4)
5x2 + 17x + 31
x2 - 3x + 4 | 5x4 + 2x3 + 0x2 - 9x + 12
5x4 - 15x3 + 20x2
17x3 - 20x2 - 9x
17x3 - 51x2 + 68x
31x2 - 77x + 12
31x2 - 93x + 124
16x - 112
Thus 5x4 + 2x3 - 9x + 12 = (5x2 + 17x + 31)(x2 - 3x + 4) + 16x - 112
Comments
Thanks!
- Jackie R. from Oklahoma City, OK 12/18/2012