2NI3(solid) --> N2(gas) + 3I2(solid)
I am unsure how to solve this problem. If I use the ideal gas equation (without referencing the chemical equation given), I get 0.134 mol NI3. However, I don't think I am doing this correctly because I didn't use the equation given and NI3 is a solid and not a gas... Please help me solve this! Thank you so much!
Liz, you are very close.
With 0.134 L you have calculated the number of moles of N2 gas you need to fill a 3 L container at STP. The equation tells you that every 2 moles of NI3 gives you 1 mole of N2. That means you need twice as much NI3. Multiply your answer by 2 to get the number of moles of NI3 that produces the necessary amount of gas:
0.268 moles of NI3
Or, with significant figures of the question: 0.3 moles.
Use molar ratio: 2 moles of NI3 can produce 1 mole of N2.
Now use dimenstional analysis:
(3L)(1 mole of N2/22.4 L)(2 moles of NI3/1 mole of N2) = 0.268 moles of NI3.
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Attn: What you got is the number of moles of N2, not NI3. You have to use the chemical equation to get the molar ratio.
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