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Lee J.

Former college math/statistics instructor

Tacoma, WA (98433)

Travel radius
19 miles
Hourly fee
$45.00
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It suppose to be (x^3-8)/(x^2-4)   x^3-8 = (x-2)(x^2+2x+4) x^2-4 = (x-2)(x+2) therefore, (x^3-8)/(x^2-4) = (x^2+2x+4)/(x+2)  <-- (x-2) cancelled out. The answer is (x^2+2x+4)/(x+2)     Lee

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