mean = sum of x*P(x) = 2x0.50 + 8x0.30 + 10x0.20 = 5.40 variance = sum of x^2*P(x) - mean^2 = 2^2*0.50 + 8^2*0.30 + 10^2*0.20 - (5.40)^2 = 2.00 + 19.20 + 20.00 - 29.16 = 12.04 I hope you understand how the answer came out. Lee

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Hello, Graduated from the University of Washington and Texas A n M University, I have lots of teaching experience in mathematics and statistics as I was a math/stat instructor at University of Alaska Anchorage and University of Maryland University College Asia. Wish to tutor you with my best knowledge in Math/Stat.

I am amazed at how wonderful Lee J, my tutor in statistics, is! I am getting an "A" in statistics and hope to keep my grade right there. I am certain to with Lee's help. Thank you.

Lee is thorough and patient. He is really good at finding out why you are having trouble with a concept and helping explain it. I can't thank him enough.

Lee is very knowledgeable about the math subject we met about. He was easy to understand and quick to adapt to my level. Thank you Lee.

He is an excellent mentor in statistics. He was very patient and explained everything with details and examples. I recommend this tutor 100%!

Math:

ACT Math, Algebra 1,
Algebra 2,
Science:

Physical Science, Physics
Language:

Korean
Elementary Education:

Elementary Math
Business:

GMAT, GRE
Homeschool:

Algebra 1,
Algebra 2,
Test Preparation:

ACT Math, ASVAB, GED, GMAT, GRE, SAT Math
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I was an adjunct faculty at University of Alaska Anchorage from Jan 1992 to May 1999 and I taught Introductory Algebra, Intermediate Algebra, College Algebra and Calculus. Also, I was an adjunct/associate professor at University of Maryland University College (Military Overseas Education Program) from year 2000 to year 2007 and I taught Introductory Algebra, Intermediate Algebra, College Algebra, Calculus and Statistics.

When I was a UW student, after I took differential equations, I tutored this subject to college students.

Also, as an Electrical Engineering student, I studied about Laplace Transform and Fourier Series.

I can tutor up to college level students.

Lee J

I was born in Korea and spent 25 years. After that, I came over States and attended University of Washington. I can read and speak Korean as a native Korean.

Tutors have the ability to create educational resources and share them with the WyzAnt community. Here are some of the resources created by Lee. View all of Lee’s resources

mean = sum of x*P(x) = 2x0.50 + 8x0.30 + 10x0.20 = 5.40 variance = sum of x^2*P(x) - mean^2 = 2^2*0.50 + 8^2*0.30 + 10^2*0.20 - (5.40)^2 = 2.00 + 19.20 + 20.00 - 29.16 = 12.04 I hope you understand how the answer came out. Lee

how do you simplify x^3-8/x^2-4? (answer)

It suppose to be (x^3-8)/(x^2-4) x^3-8 = (x-2)(x^2+2x+4) x^2-4 = (x-2)(x+2) therefore, (x^3-8)/(x^2-4) = (x^2+2x+4)/(x+2) <-- (x-2) cancelled out. The answer is (x^2+2x+4)/(x+2) Lee

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I am amazed at how wonderful Lee J, my tutor in statistics, is! I am getting an "A" in statistics and hope to keep my grade right there. I am certain to with Lee's help. Thank you.
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Lee will travel within 19 miles of Tacoma, WA 98433.

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