(877) 999-2681  | BECOME A TUTOR | BECOME A STUDENT  |  Sign In
Search 70,401 tutors SEARCH
WyzAnt Tutoring Tutor Tutor United States

## Kevin S.

### Seneca, SC (29678)

 Travel Radius 40 miles Hourly Fee \$30.00 Discount \$25.50 - \$28.50 Save up to 15%
 Background Check Passed 10/22/2012 Your first hour with any tutor is always 100% refundable!

# Kevin's Responses in WyzAnt Answers

#### Solve the following questions

7d2-14d-21=0

3c2+66c+63=0

6c(c-4)=2(18c+168)

+ more- less
Asked by Ashab from Fremont, CA
01

For the first two, find a common factor. In the first, pull a 7 out:

7(d2 - 2d - 3) = 0 . Now factor and solve.

For the third, distribute across the parentheses, gather like terms, and set equal to zero. If there are any common factors, pull them out and factor what is left:

6c(c - 4) = 2 (18c + 168)

6c2 - 24c = 36c + 336

6c2 - 60c - 336 = 0

6(c2 - 10 c - 56) = 0

The rest is left to the student.

#### Find the slope of the line that is perpendicular to x-y=3

Graph equation and show work step by step

+ more- less
Asked by Kelly from Baltimore, MD
30

A line that is perpendicular will have a slope that is the negative reciprocal of the slope of a given line. For example, if the slope of a line was 3, then the perpendicular line would have slope -1/3

Given x - y = 3, let's get this into slope-intercept form y = mx + b

-y = -x + 3   (now divide by -1)

y = x - 3

So our slope is 1. Therefore, the slope of our perpendicular line is -1/1 = -1

#### How do you factor 12x^2+5x-25??

I am not able to factor this.

+ more- less
Asked by Erica from Johnson City, TN
20

Factors of 25 are 1 * 25, 5 * 5

Factors of 12 are 1 * 12, 2 * 6, 3 * 4

Since we're looking for two values that, when the  difference of the products is 5, I'm thinking we need values close together... So I'm going to look at 5*5 and 3 * 4:

(3x + 5)(4x - 5)

Since the constant is -25, i knew that one of my signs was going to be negative.  Since the linear term (5x) was positive, I knew my larger product was going to be positive.

5 * 4x - 5 * 3x = 20x - 15x = 5x.

#### (4x^3+8x^2-x-2)/(x+2) =

I want to know how to solve and check my answer

+ more- less
Asked by Toni from West Bloomfield, MI
20

One method is "long division" . Using this method, you compare the leading terms of your numerator and denominator.

How many times does x (from x + 2) go into 4x3 ? 4x2 times (x * 4x2 = 4x3). So we also multiply the 2 (from x + 2) by 4x2 (to get 8x2), and now we subtract it from our numerator, and we are left with (-x-2)/(x + 2)

Now, how many times does x go into -x ? -1 times. Multiply and subtract:

-x - 2 - (-1)(x + 2) = 0

So our result is 4x2 - 1

__4x2 ______   -1  _________________

x + 2      | 4x3 + 8x2 - x - 2

4x3 + 8x2
---------------------

-x - 2
-x - 2

--------

0

#### Help with fractions that contain exponents, factoring and LCD?

I have three problems that I can't completely figure.  I appreciate any help and explanations!

17        -    6

x2-12x+35      x-7

x+7          +    x +5

x2+7x-18            x2+3x-54

I know the second fraction needs to be flipped so it can be multiplied.

7c+49   Divided by    c2-49          So it would become:   7c+49   X    7c              Then:  (7c+49) X 7

3                           7c                                                    3             c2-49                         3(c2-49)

+ more- less
Asked by Courtnee from Mitchell, IN
10

When finding the LCD, it is often helpful to factor the denominators, then see what you have:

In the first problem, our denominators are

x2 - 12x + 35     and x - 7

x2 - 12x + 35  factors into (x - 5)(x - 7).

So your LCD is (x - 5)(x - 7)

So, multiply the second term by (x-5)/(x-5) to get your new fractions:

17/[(x - 5)(x - 7)] - [6(x - 5)]/[(x - 5)(x - 7)]

simplify the second numerator and rewrite:

[17 - 6x +30]/[(x - 5)(x - 7)] = [ -6x + 47]/[(x - 5)(x - 7)]

======

For the second one, approach the LCD the same way. You'll just wind up with three factors in the denominator as opposed to two

For the third, you've got a good start. Now factor 7 from (7c + 49) and factor (c2 - 49) and I think you'll see terms that you can reduce.

## Other Seneca, SC Tutors

### Kevin's Hourly Rate

Hourly Fee: \$30.00

Save up to 15% with a discount package

Cancellation: 8 hours notice required

#### How do I receive a discount?

Save between 5 and 15% on tutoring by purchasing credit with one of our prepaid discount packages. You can buy one of our standard 5, 10 or 15% packages or customize your own package based on how much tutoring you need. The credit you purchase can be used towards any tutor at any time and does not expire. If you do not use the entire package, we will simply deduct what you did spend on tutoring from your original purchase price and give you a refund. Discount packages start as low as \$190.

Credit For Only You Save
\$200 - \$399 \$190 - \$379 5%
\$400 - \$999 \$360 - \$899 10%
\$1,000 + \$850 + 15%

Your first hour with any tutor is protected by our Good Fit Guarantee: You don't pay for tutoring unless you find a good fit!

## Background Check Status for Kevin S.

Kevin S. passed a background check on 10/22/2012. You may run an updated background check on Kevin once you send an email.