What you have to do in such a case, is to muliply each term of each factor by each term of other factors. As ax+bx = (a+b)x, (a+b)(x+y) = (a+b)x+(a+b)y = ax+bx+ay+by, so (a+b)(x+y) = ax+ay+bx+by. Here, one way is to first distribute...
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