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Will M. for tutoring lessons in Cleveland OH Over 100 tutoring hours WyzAnt Tutoring Tutor Tutor United States

Will M.

Chemistry tutor who gets that teachers don't get it.

Cleveland, OH (44126)

Travel Radius 25 miles
Hourly Fee $40.00
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  57 ratings

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Will's Responses in WyzAnt Answers

a molecule having a covalent bond can be ionic true or false?

it is a true or false question

 

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Asked by Greg from Grand Rapids, MI
20

Will's Answer:

Actually, this is true.  Sodium Carbonate, Na2CO3, is an ionic compound that contains covalent bonds within the carbonate anion. 

log MN=log + log

how do i work problem logMN=log      + log       

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Asked by Nastassia from Cortland, IL
00

Will's Answer:

If I understand the question, this is just a property of logs.  The log of a product is the sum of the logs. 

 

log (M * N) = log (M) + log (N)

calculate the molecular weight of CO in g/mol.

what is the asnwer?

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Asked by Shana from Westfield, IN
00

Will's Answer:

The periodic table will give you the answers you are looking for here.  The molar mass of oxygen is 16.00, and Carbon is 12.01.  Adding these together you get a total of 28.01g/mol, rounding everything to two decimal places.

calculating the van't Hoff factor

When 9.12 g of HCl was dissolved in 190 g of water, the freezing point of the solution was -4.65oC.  What is the value of the van't Hoff factor for HCl?

Here is what I did-

I know that I use: deltaT= Kf x m x i

rearranged to solve for i: deltaT/Kf x m

 

solving for molality:

mol HCl=0.250

kg solvent= .190

m=0.250/.190= 1.32

 

i= -4.65oC/1.86 x 1.32 = -1.89

I am not sure if the value for i can be negative or if I did the problem correctly.  Please help me!  Thanks!

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Asked by Michael from Crown Point, IN
01

Will's Answer:

the Van't Hoff factor is always positive.  Kf for water is -1.86 Kelvin/molal.  Your works is otherwise correct, you're just missing the negative sign on Kf.  Hope this helps.

 

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Background Check Status for Will M.

Passed

Will M. passed a background check on 2/18/2013. You may run an updated background check on Will once you send an email.

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