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Jon G. for tutoring lessons in Albuquerque NM WyzAnt Tutoring Tutor Tutor United States

Jon G.

Areas: Math, sciences, NM & Native Amer. history, A&P, HS coach

Albuquerque, NM (87181)

Travel Radius 40 miles
Hourly Fee $35.00
Discount $29.75 - $33.25 Save up to 15% (i)

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Jon's Responses in WyzAnt Answers

What is the area of the triangle in cm

7 is on the base of the triangle & 13 is on the right side of the triangle

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Asked by Gavin from Bentonville, AR
00

Jon's Answer:

Gavin...are the measures to your triangle in cm's If they are...then the formula you should commit to memory...write it on your hand...or something....is area(of a RIGHT ONLY triangle!!) = one-half base times height[in words] but in an equation...a = ½(b × h), If its not a RIGHT TRIANGLE...then its another formula. Those you should commit to memory as well...write them on your pillow(if your mom let's you).

And another question...if your measures aren't in 'cm'...then you should know how to change whatever measures you have...ie...inches...feet...meters...miles...whatever...be able to convert them to cm's.

I'll be glad to help...

J

What is 3/4(Square Root of 45)?

Change each radical to simplest radical form

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Asked by Barbie from Patriot, OH
00

Jon's Answer:

think of this...what is 3/4 of 100...how do you solve this? what is the answer? lets do a simple one

What is 1/2 of 100?   let's multiply 1/2 and 100     so      1/2 x 100  which is 1/2 x  100/1...correct??

 we know the answer is 50, right? we get this by multiplying 1 times 100...the numerator and 2 times 1,

the denominator...correct? now we have 100/2...correct? do you see? just complete the division operation,

which is 100 ÷ 2 = 50   correct?

now you do your problem...3/4 x √45      which is the same as 3/4 x √45/1...

now you have    3 x √45/4 x 1     so simplify   3√45/4...complete the operation...try more problems

the more you work the easier they will become

how do you find the square root

i need to know because i have staar tuesday

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Asked by Lola from Houston, TX
00

Jon's Answer:

Lola...hello...your question is intriguing. If you are allowed to use a calculator, 

Finding the square root of a number is simple...using the calculator....enter in the

number you're trying to find the square root, let's say 49. Okay, enter in 49...you'll

see that on your screen. then press the square root key...that has this symbol...√¯¯

usually the answer is on the screen...if not...then press enter and you should see

the value '7' appear on our screen. Try it with other numbers. I don't have to tell you

that the square root is a number that when multiplied by itself will give  a specific value.

let's take the value 8..    8 ×  8 = 64    correct??  We say that the square of 8 is 64 and 

then we also say the square root of 64 is 8. Got that? Try it with other number...I'll

give you a few examples...starting with 1...so this is a number squared:

Okay...what if you don't have a calculator. Well all I can say is draw up a square

root chart...very much like a multiplication table. On the top line...starting with 1

and go...let's say 2. this will be the horizontal line. Do the same with a vertical line

at a right angle, but go to 5. Now, just like a multiplication table starting multiply 

vertical line in the 1's column by 1...so there will be 1...2...3...4...5, because any number

times one will be that number. Now  in the 2's column...you're going to multiply each

of the vertical numbers by the themselves ...so each number is squared...example:

1...4...9...16...25 this is 1...2...3....4...and 5 multiplied by itself. see if you can make a 

larger table...on the vertical line say 1 to 12...and on the horizontal line...go as many

times as you can...WITHOUT A CALCULATOR....practice with this and you will become

familiar with each number squared. Good luck

How do you figure out interior angles when given exterior angles

I don't really  know how to explain but basicly i have the exterior angel of 25 degrees on the inside which happens to be on the same side and has the diagonals says 10 degrees on top and the variable V on the bottom  . On the side with no diagonals says 155 degrees then under that says the variable C.C also happens to be apart of the diagonals the other angel has nothing because we don't. Need to answer it.     

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Asked by Jourdan from Neenah, WI
00

Jon's Answer:

Jourdan...I'm limited by the functions of this e-mail...so I'm going to describe it to you, so that you and put a visual picture and it will help answer your own question. I'm going to describe it to you, step by step, and if you will draw it. Jourdan...I'm assuming you know the definitiond of some of the words I use. Step 1 On your sheet of paper, draw to parallel lines...(remember the definition of two parallel lines)...now that you have drawn the lines...draw a third line which intersects with the two lines...its gonna look like a railroad track with a telephone pole that fell across it at an angle and touching both lines at some point. Not at a right angle, or straight across. Step 2 This configuration creates 8 angles, 4 on one line and 4 on the other line, correct? Can you see that? this is where the rules and axioms come into play which defines 2 parallel lines. Step 3 Pick one of the lines that intersect, with 4 angles. If the lines are not right angles, you will have one group of angles, one larger than the other... that's if the lines do not create right angles. Look under the parallel line, you will see similar lines, that are upside down and reversed. Step 4 The point where the two lines intersect, the vertex, one of the angles is larger than the other. BUT...But...together, they create a straight line. Let's say one angle is Angle A, the larger angle, and the other angle, which is smaller, Angle B.(notice I have not used any measurement, like degrees!!!) SO...now we have the equation below. Angle A + Angle B = a straight line RIGHT!!!! Step 5 Look at where the lines intersect. There are 4 angles, RIGHT! We said Angle A was the larger angle. NOTICE...right across Angle A is another angle with is very similar. The angle is right across and under Angle B. Let's label that Angle D. Step 6 Since Angle D is under Angle B notice that being next to one another they create a straight line...created by the intersection of one line to another. Since Angle B and Angle C create a straight line. So we can say: Angle B + Angle D = a straight line RIGHT!! See that !!! Step 7 But remember: Angle A + Angle B = a straight line right!! But we also saide Angle B + Angle D = a straight line RIGHT!!!! Do you see what happened here.... we can say Angle B = Angle B Right!!! If this is true Angle A = Angle A and Angle D = Angle D RIGHT!! But we also said Angle A + Angle B = a straight line a nd Angle B + Angle D = a straight line And since a straight line is going to equal a straight line....we can say Angle A + Angle B = Angle B + Angle D And since Angle B = Angle B....we can then say: Angle A + Angle B = Angle B + Angle D so Angle A = Angle D With all of this said...now but in the degrees of the angles created by intersecting two parallel lines. Draw the two lines, put the degree marks in and complete the addition as about. We add because a line is 180*(degrees) CORRECT!!!! THEN WE CAN SAY: Angle A + Angle B = 180* Angle B + Angle D = 180* So if Angle A is 100* what is Angle B? Angle A + Angle B = 180* Angle A = 100* 100* + Angle B = 180* SO!!!! Angle B = 180* - 100* Angle B = 80* Right!!! Now...put in your values for your angles and see if they work out that way. Good luck..work..using the concepts outlined..then you will be the MASTER!!

x * x - 5x + 6

The x is actually x squared. Whats the answer?

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Asked by Ashley from Bellevue, ID
00

Jon's Answer:

Ashley...when you came across this problem...did you know what the solution would look like? I'm assuming that you knew what the problem was requiring you to do was find the values, that when multiplied together would give you the equation. x^2 - 5x + 6 The problem is asking you to find out what values, in this case, binomials, that when multipled together gives you the trinomial x^2 - 5x + 6 So what you're doing is dividing...in this case...finding the factors of the trinomial.. x^2 - 5x + 6 With that said, I'm assuming that you know your solution would be like: ( ? - ? )( ? - ? ) Correct? The problem is asking you to find the factors of the trinomial. Hint 1: The signs inside the trinomial tell you the signs inside the parenthesis will both be negative, like below. ( - )( - ) Hint 2: the first values of the binomials will be x, because (x)(x) = x^s ( x - )( x - ) Hint 3: I'm assuming you know the FOIL methiod used in multiplying...and if you don't ask your instructor/teacher to help you with that, or you're welcome to drop me a line. Hint 4: The last value in x^2 - 5x + 6 is 6 at this point, the factors of 6 need to be identified...the values that when multiplied together the product is 6. The factors of 6 are 1, -1, 2, -2, 3, -3, 6, and -6...right, because 1 x 6 ... 2 x 3 ... -1 x -6... -2 x -3 correct? Well it is. Now here's a step that you can use Step 5: Filling in the parenthesis. Another way to find the other values in side the parenthesis. Look at each of the groups of factors. Take each group of factors and add the two values together: 1 + 6 = 7 and 2 + 3 = 5 -2 + -3 = -5 -1 + -6 = -7 Look at the sums of each of these...there is 5, -7, 7 and the other is -5. Notice that one group, the sum of the two factors is the same middle value in the trinomial This helps you determine with values you'll put in the parenthesis (-2,-3) so the solution would be ( x - 3 )( x - 2 ) or ( x - 2 )( x - 3) Here's another tool you can use to help you with these kinds of questions. See if it works with other similar kinds of problems. I hope this helps and the more you do these kinds of problems....then you'll be the MASTER

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