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## Biostatistician / Statistician

### Omaha, NE (68154)

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# Sandeep's Responses in WyzAnt Answers

#### 2x+/x+4= 0

fraction ineqaulties

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Asked by Mubashar from Brooklyn, NY
00

#### i dont understand this problem 2x + 7 < x-4

I need to solve for x

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Asked by Isaiah from Rapid City, SD
00

2x+7 < X-4

substract x from both sides

2X+7 -X < X-4-X

or  X+7 < -4

now substract 7 from both sides

X+7-7 < -4-7

or X < -11

#### Solve the system using elimination.

2x+5y=14

3x-2y=-36

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Asked by Brittany from College Station, TX
00

2x+5y = 14   ---equation 1

3x-2y= -36  ----equation 2

multiply eq. 1 by (-3) and eq.2 by 2 and add the two equations-

-6x - 15 y = -42

6x-4y       = -72

_________________

-19y =- 114

y = 6

2x + 5*6 = 14

2x = 14-30 = 16

x = -8

#### Statistics with chi square

Race of Offenders

Type of Lawyer. White    Nonwhite.   Total

Private.                 95.        25.         120
(47.5%). (8.3%)
Court appointed  105.         275.      380
(52.5%). (91.7%)
Total.                   . 200.       300.       500

Instructions: Analyze the following table. Use the observed frequencies in the table to calculate chi square. . Show your findings in a table with chi square (Chi square = 100.9 with 1 degree of freedom).

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Asked by Tarah from Suffolk, VA
00

You have 4 cells with frequescise in your problem -

95 , 25, 105 , 275

best way to do this problem is make  2X2 table and put observed and expected frequencies in the table.

as explained above to calculate expected frequency you will take row total & column total & devide by grand total for each cell.

so for 95 - Exp freq = (120*200/500) = 48

for     25 - Exp freq = ( 120*300/500) = 72

for    105 Exp Freq  = ( 380*200/500) =  152

for    275   Exp Freq = ( 275*300/500) = 228

Now calculate this for each cell  (Observed - Expected) ^2/ Expected and add them -

( 95-48)^2/48 + (25-72)^2/72 + ( 105-152)^2/152  + ( 275-228)^2/ 228 = 46.02 + 30.68 + 14.53 + 0.69 = 100.9

degrees of freedom = (# of rows -1 ) ( # of columns-1) = ( 2-1)(2-1) = 1

let me know if you have any questions or you don't understand anything.

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