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## Successful Educator, since 1993

### Saint Louis, MO (63141)

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# Charles's Responses in WyzAnt Answers

#### multiply and simplify

multiply and simplify (x^2+x-12/x-3)*(x^2-2x-3/x^2+5x+4)

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Asked by Tylier from Newport, TN
00

I'm going to assume the following problem is what you meant.  Let me know if not.

(x2+x-12)/(x-3) * (x2-2x-3)/(x2+5x+4)

This is a question really testing your ability to factor the polynomials involved.  Once you do that it is fairly easy.  Here's what it looks like after factoring each of the polynomials:

[(x-3)(x+4)]/(x-3) * [(x-3)(x+1)]/[(x+4)(x+1)]

If you write this out on paper it is easier to see what to do.  In the first fraction you'll see that there's an (x-3) in the top and the bottom, so they cancel to 1, leaving only an (x+4) in the top.  The second fraction has an (x+1) in the top and bottom which also cancels to 1.  This leaves us with (x+4)(x-3) in the top of the new fraction and (x+4) in the bottom.  The two (x+4) factors cancel to 1 leaving you with the very simple final answer of (x-3).

Write it out on paper and it will be easier to follow what I've said here.  Hope that helps.

Charlie Gibson

#### 7/a^5+4/3a

Simplify 7 divided by a to the fifth plus 4 divided by 3a

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Asked by Jim from Shorewood, IL
00

Hi Jim,

Without parentheses this expression means that the addition is done last, therefore the first thing to do is to modify the form of each of the two fractions so they each have the same denominator (bottom number).  You do this by multiplying each fraction by some form of 1.  For the first fraction multiply it by 3/3 giving you 21/3a5.  For the second fraction multiply it by a4/a4 giving you 4a4/3a5.  Notice that we have now converted each fraction to a form with 3a5 in the denominator and yet we've not changed the value of either fraction.  We've only changed the form; just like 2/4 and 1/2 are two forms of the same fraction.  Once the denominators are the same, the addition is simple:

21/3a5 + 4a4/3a5 = (21+4a4)/3a5

Charlie Gibson

#### why cant a line (with arrows) go over the quadrant its in?

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Asked by Audrey from Saratoga, CA
00

Hi Audrey,

Can you clarify the question you are asking?  I think I am missing something.  Sometimes teachers need their student's help too.  Can you help us understand your question better?

Charlie Gibson

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## Background Check Status for Charles G.

Charles G. passed a background check on 7/1/2011. You may run an updated background check on Charles once you send an email.