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I am retired, so increasing my income is ok, but I find that as I interview my students, many of them have difficulty understanding what the teacher is trying to convey. I love math and hope that I can help the students I work with to enjoy math as much
as I do.
OK. This is using the basic slope y-intercept equation of old. Let f(x) = lnx.
Then f(1) = 0, f'(x) = 1/x and f'(1) = 1
In other words, let your point be (a, f(a)) instead of (x1, f(x1)) and m = f'(a)
Since x = 1, let x1 = a = 1.
let y = -sin(x+5) - 9.
exchange y and x.
x = -sin(y+5) - 9
Solve for y: sin(y+5) = -x - 9.
How do you solve this? Try using the inverse sin of each side.