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Alejandro L. for tutoring lessons in Cambridge MA Over 100 tutoring hours WyzAnt Tutoring Tutor Tutor United States

Alejandro L.

Chemistry tutor (all areas) + Intro Astronomy

Cambridge, MA (02138)

Travel Radius 5 miles
Hourly Fee $40.00
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  29 ratings

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Alejandro's Responses in WyzAnt Answers

Hi, I'm stuck with the following chem problem:So I can't paste it but will describe.

I have (3S,4S)-3-bromo-3,4-dimethylhexane but I don't know based on on the given picture why that is. I cannot post the picture but here the description.

I start out with two carbons, then use solid lines to position Bromine and hydrogen opposite each other along the two carbons. So carbon 1 on the sketch has Bromine facing up and carbon 2 facing down.

Then I add the other two groups on each carbon.

Carbon 1 has ethyl group on nonsolid wedge (facing away from the picture) and methyl group with solid wedge (facing towards me)

Carbon 2 has ethyl group on solid wedge (facing towards me) and methyl group on nonsolid wedge (facing away).

The dilemma: I get how carbon 1, which really is carbon 3 in the whole parent chain, is S configuration. But how I don't get how carbon 2, which really is carbon 4 in the whole parent chain, is S configuration. How are you prioritizing the groups around carbon 4 which I refered to as carbon 2 to start with?

Please help!

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Asked by Jason from Raleigh, NC
00

Alejandro's Answer:

I will draw the Fisher projection for (3S,4S)-3-bromo-3,4-dimethylhexane below:


Fischer projection:

       Br

Et---C---Me

Et---C---Me

       H

where the ethyl and methyl groups point towards you and the Br and H groups point away from you.  In the structures above, the priorities for C-3 are:


Priority 1 = Br

Priority 2 = CHMeEt

Priority 3 = ethyl

Priority 4 = methyl

For C-4 the priorities are:

Priority 1 = CMe(Et)(Br)
Priority 2 = Ethyl

Priority 3 = methyl

Priority 4 = H

If a temperature scale were based off benzene.

If a temperature scale were bassed on the freezing point (5.5 degrees Celsius) and boiling point (80.1 degrees Celsius) of benzene, and the temperature difference between these two points was divided into 50 units called degrees X, what would be the freezing and boiling points of water in degrees X?

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Asked by Angela from Decatur, GA
00

Alejandro's Answer:

Whenever you want to derive a temperature scale or make-up a new entirely, it is easiest to use some basic Calculus.  First, the difference of the temperature in Celcius is (80.1 - 5.5 = 74.6), while the difference in the new unit is X is simply 50 because the problem tells you that's how many units of X there'll be.  As a result, the derivative of degrees X with respect to degres C is given by:

dX/dC = (50)/(74.6) = 0.67

Moving dC to the right side of the equation and integrating gives you:

Integral(dX) = Integral(0.67dC)

X = 0.67C + constant

Now, you let the the melting point of benzene be 0 degrees X or X = 0 and since the melting point in Celsius is 5.5 or C = 5.5, you can solve for the constant:

0 = 0.67(5.5) + constant

- 3.7 = constant

Thus the equation for converting to degrees Celcius to degrees X is:

X = 0.67C - 3.7

Now, using this equation we can determine the melting and boiling points of water by plugging 0 and 100 for C and solving for X:

X(mp H2O) = 0.67(0) - 3.7 = -3.7

X(bp H2O) = 0.67(100) - 3.7 = 63.3

for x is not equal to 0, what is the limit of 1/h[ (1/ x + h) - (1/x) ] when h approaches 0 - Kathryn T. from Houston, TX

I'm not sure how to approach this equation for Calculus.

 

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Asked by Kathryn from Houston, TX
00

Alejandro's Answer:

You need to add the fractions together:

 

(1/h){[1/(x+h)] - [1/x]} = (1/h){-h/[x(x+h)]} = -1/[x(x+h)]


Now you can apply the limit to the function above:


lim(h-->0) -1/[x(x+h)] = -1/(x^2)

(2,-2) slope=2 how to put it in slope intercept form

i cnt figure out how to do this

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Asked by Edgar from Kissimmee, FL
11

Alejandro's Answer:

The equation of a line is given by:


y = mx + b


where m = slope = 2 and therefore y = 2x + b.  Since x = 2 and y = -2 (this is given by the point at (2,-2)), you can solve for b:

 

-2 = 2(2) + b

-2 = 4 + b

-6 = b

 

Thus the equation of the line that passes through the point (2, -2) and has slope = 2 is

 

y = 2x - 6

 

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