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Stephen H. for tutoring lessons in Gainesville FL Over 20 tutoring hours WyzAnt Tutoring Tutor Tutor United States

Stephen H.

Quick and Easy help with Math, Physics and Engineering

Gainesville, FL (32608)

Travel Radius 35 miles
Hourly Fee $35.00
Discount $29.75 - $33.25 Save up to 15% (i)

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Stephen's Responses in WyzAnt Answers

how to set up proportions?

for example ''Mrs. Stearns need to photocopy a 9.5 cm wide by 16 cm long picture. She wants to enlarge the picture so its length is 40 cm. How wide will the picture be?'' i need help on these kind of problems i will be getting a tutor soon so watch out. and please help me online with my homework because i might get kicked out of my upper level [above grade level] math class so please help me! i greatly appreciate all your help!!!

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Asked by Sarah from Anoka, MN
10

Stephen's Answer:

Proportions are ratios. A ratio is simply one dimension divided by another. Example is Width/Length. Mrs. Stearns most likely wishes the Width/Length ratio for her new photocopy to stay the same as old one. 1) Width (old)/Length (old)= Width (new)/Length (new)...this is the form of the calculation to be made. 2) We know Width (old) = 9.5cm, Length (old)= 16cm, Length (new) = 40cm as givens. 3) We want to calculate Width (new) so rearrange 1) as below: 4) Width(old)/Length(old)*Length(new)=Width(new) 5) Width(new)= 9.5/16*40= 23.75 cm

Pentagon shape with one pair of parallel sides

Please send the shape as asked above

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Asked by Jodi from Novi, MI
10

Stephen's Answer:

It would look like a house from the front with a peaked roof and two parallel walls. The roof is two lines, the floor a third, the two walls totalling five.

A=bh A=45b=15

A= bh A=45,b=15  Area of paralleglogram

 

 

 

 

 
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Asked by Regina from Merced, CA
10

Stephen's Answer:

The A=bh looks like Area = Base X Height which is the formula for the area of a rectangle (or parallelogram). Assuming that then the Area is given as 45 and the Base is given as 15, the Height could then be found as 45/15=3.

3.Which table identifies only points (x,y) such that, when graphed, they lie on the line ?

Here are the tables...

 A.
x -5 -3 0 1
y 31 21 6 1

B.
x -4 -2 -1 0
y 14 10 8 6

C.
x 21 15 6 3
y -5 -3 0 1

D.
x -4 -2 -1 0
y -6 0 3 6

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Asked by Ciara from Plano, TX
00

Stephen's Answer:

From the given information, one way to proceed is to calculate the slope between each of the four points. If the slope is a constant then look for a constant y-intercept among the four points. If both the slope and y-intercept is constant, the points are all on the same line.

slope = (y2-y1)/(x2-x1) & y-intercept = (y1*x2-y2*x1)/(x2-x1)

use the above formulas to show that for each group the slope and y-intercept is constant. Therefore all groups are points on a line but no two groups are of the same line

 

 

 

6. If the slope of the equation is changed to and the y-intercept is changed to (0, -4), which statement best describes this situation?

Here are the answer choices 


A The new line is perpendicular to original line.
B The new line is parallel to the original line.
C The new line and the original line have the same y-intercept.
D The new line and the original line have the same x-intercept.

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Asked by Ciara from Plano, TX
00

Stephen's Answer:

There is missing information for this problem. We need information regarding the initial line in order to compare the final line and the initial line.

a) If I were to create some information about the initial line so that the (slope, y-intercept) is (0,0), then we can say that the initial line and new line have the same slope, therefore parallel. Choice B would apply.

b) If the initial line were (1,-4), then we can say both lines have the same y-intercept. Choice C would apply.

c) Since the new line has a slope of zero, it is parallel to the x-axis and cannot intercept it. Choice D would always be wrong.

d) If the initial line has a slope of infinity, then it is perpendicular to the new line. Choice A would apply.

Stephen's Hourly Rate

Hourly Fee: $35.00

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Background Check Status for Stephen H.

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Stephen H. passed a background check on 4/21/2013. You may run an updated background check on Stephen once you send an email.

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