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### Chula Vista, CA (91911)

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# Danielle's Responses in WyzAnt Answers

#### the ratio of the areas of the two squares if 25 to 9. The length of one side of the smaller square is 30 meters. how long is one side of the larger square

how long is one side of the larger square

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Asked by Sandra from Denver, CO
10

To start, you need to write a proportion using the given numbers. The numbers for the smaller square and larger square should be on opposite sides of the equal sign:

9/302 = 25/x2

Using order of operations, solve the exponent first: 30*30=900

You should now have: 9/900 = 25/x2

Simplify the fraction on the left by dividing by 9: 1/100 = 25/x2

Cross multiply: x2 = 2500

Take the square root of 2500 to solve for x: x = √2500

Your answer for the length of a side of the larger square is: x = 50

#### How do I figure out what 2(-5) answer is

How do Ifigure this out

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Asked by Robert from Chula Vista, CA
10

You have to multiply the 2 numbers. Keep in mind that a positive times a negative is a negative number.

2 * -5 = -10

#### x-.098x=130.11

hw do I solve for this?

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Asked by Marilyn from Clover, SC
00

Pretending that there is a 1 in front of the first x, subtract .098x from 1x: 1x-.098x=.902x

Now you have: .902x=130.11

Divide by .902 on both sides: .902x/.902=x and 130.11/.902=144.246

#### 3(2(x-3)+2)+5(x-3)

3(2(x-3)+2)+5(x-3)

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Asked by Connie from Memphis, TN
00

Separate the 2 parts of the problem: 3(2(x-3)+2) and 5(x-3)

Starting with 3(2(x-3)+2), distribute the first 2 to x-3:

2(x-3) = 2x-6

Now you have: 3(2x-6+2)

Distribute the 3: 6x-12

Now you can work on the other part of the problem, 5(x-3).

Distribute the 5 to x-3: 5x-15

Put the 2 pieces back together: 6x-12+5x-15

Simplify it to get the answer: 11x-27

#### Least common denominator

How do I find the LCD of k2+k-42/1-k and k2-k-30/k-1

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Asked by Carla from Duarte, CA
00

To find the LCD you only have to focus on the denominators of each fraction: 1-k and k-1

Multiply them to each other by using the FOIL method: (1-k) * (k-1) = k-1-k2+k

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